What volume will 4.2 moles of neon has occupy at 27 degrees Celsius and a pressure of 47.2 kPa?
回答 (1)
2018-04-13 1:02 pm
No. of moles, n = 4.2 mol
Temperature, T = (273 + 27) K = 300 K
Pressure, P = 47.2 kPa
Gas constant, R = 8.314 J / (mol/K)
Gas law: PV = nRT
Volume, V = nRT/P = 4.2 × 8.314 × 300 / 47.2 L = 222 L
Temperature, T = (273 + 27) K = 300 K
Pressure, P = 47.2 kPa
Gas constant, R = 8.314 J / (mol/K)
Gas law: PV = nRT
Volume, V = nRT/P = 4.2 × 8.314 × 300 / 47.2 L = 222 L
收錄日期: 2021-05-01 22:25:30
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