Hw help: A 4 ohm, 5 ohm and 14 ohm resistor are wired in series with a 9 V battery. What is the current going through the circuit?
回答 (2)
2018-04-13 12:59 pm
✔ 最佳答案
I = V/(r1+r2+r3) = 9/(4+5+14) = 9/23 = 0.391 A
2018-04-13 10:03 am
Resistors in series simply add.
4 + 5 + 14 = 23 ohms.
Ohms law say that I = E/R, so
I = 9/23 = 0.391 amps or 391 mA.
4 + 5 + 14 = 23 ohms.
Ohms law say that I = E/R, so
I = 9/23 = 0.391 amps or 391 mA.
收錄日期: 2021-05-01 20:58:17
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