at constant volume the temperature of 2.0 atm of gas was 325 K. the temperature is increases to 400 K. What is the new pressure of the gas?
回答 (2)
2018-04-09 10:52 am
Initial: P₁ = 2.0 atm, T₁ = 325 K
New: P₂ = ? atm, T₂ = 400 K
For a fixed amount of gas at constant volume: P₁/T₁ = P₂/T₂
New pressure, P₂ = P₁ × (T₂/T₁) = (2.0 atm) × (400/325) = 2.46 atm
New: P₂ = ? atm, T₂ = 400 K
For a fixed amount of gas at constant volume: P₁/T₁ = P₂/T₂
New pressure, P₂ = P₁ × (T₂/T₁) = (2.0 atm) × (400/325) = 2.46 atm
2018-04-09 10:52 am
(2.0 atm)(400/325) = about 2.5 atm but use a calculator.
收錄日期: 2021-04-24 01:02:44
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