更新1:
thanks guys!!
Chemistry titration help!!!!?
2018-04-09 10:05 am
If you wanted to neutralize 4.00g NaOH, what volume (1) of 1.0 M HCl would you need?
回答 (3)
2018-04-09 10:15 am
Molar mass of NaOH = (23.0 + 17.0 + 1.0) g/mol = 40.0 g/mol
No. of moles of NaOH = (4.00 g) / (40.0 g/mol) = 0.100 mol
Balanced equation for the reaction :
NaOH + HCl → NaCl + H₂O
Mole ratio NaOH : HCl = 1 : 1
No. of moles of HCl needed = No. of moles of NaOH = 0.1 mol
Volume of HCl needed = (0.100 mol) / (1.0 mol/L) = 0.10 L = 100 mL
No. of moles of NaOH = (4.00 g) / (40.0 g/mol) = 0.100 mol
Balanced equation for the reaction :
NaOH + HCl → NaCl + H₂O
Mole ratio NaOH : HCl = 1 : 1
No. of moles of HCl needed = No. of moles of NaOH = 0.1 mol
Volume of HCl needed = (0.100 mol) / (1.0 mol/L) = 0.10 L = 100 mL
2018-04-09 10:12 am
4g is 0.1 mole NaOH
1.0M HCl X 0.1L = 0.1mole HCl
0.1 L HCl is needed = 100 mL
1.0M HCl X 0.1L = 0.1mole HCl
0.1 L HCl is needed = 100 mL
2018-04-09 10:12 am
The mass of one mole of NaOH is 40 grams. So we have 0.1 mole of sodium hydroxide. 0.1 mole of hydrochloric acid will neutralize it.
0.1 = V * 1
V = 0.1 liter
0.1 = V * 1
V = 0.1 liter
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