I have another chemistry question?
2018-04-05 11:44 pm
a sample of gas is placed in a 25 L container at STP. A second sample of the same gas containing the same number of molecules, at the same temperature, is forced into the container. What will be the pressure in the container?
回答 (3)
2018-04-05 11:54 pm
When the same number of molecules, at the same temperature, is forced into the container, the number of moles of gas in the container is doubled.
Initial: n₁ = n, P₁ = 1 atm
Final: n₂ = 2n, P₂ = ? atm
Gas law: PV = nRT where V, R and T are constant.
P/n = RT/V = constant
Hence, P₁/n₁ = P₂/n₂
Final pressure, P₂ = P₁ × (n₂/n₁) = (1 atm) × (2n/n) = 2 atm
Initial: n₁ = n, P₁ = 1 atm
Final: n₂ = 2n, P₂ = ? atm
Gas law: PV = nRT where V, R and T are constant.
P/n = RT/V = constant
Hence, P₁/n₁ = P₂/n₂
Final pressure, P₂ = P₁ × (n₂/n₁) = (1 atm) × (2n/n) = 2 atm
2018-04-06 1:49 am
starting with this form of the ideal gas law
.. P1V1 / (n1T1) = P2V2 / (n2T2)
rearranging for P2
.. P2 = P1 * (V1 / V2) * (T2 / T1) * (n2 / n1)
noting that.. V1 = V2 and T2 = T1... so that those terms drop out
.. P2 = P1 * (n2 / n1)
solving.. and noting that n2 = 2 * n1
.. P2 = 1 atm * (2 * n1 / n1) = 2 atm
.. P1V1 / (n1T1) = P2V2 / (n2T2)
rearranging for P2
.. P2 = P1 * (V1 / V2) * (T2 / T1) * (n2 / n1)
noting that.. V1 = V2 and T2 = T1... so that those terms drop out
.. P2 = P1 * (n2 / n1)
solving.. and noting that n2 = 2 * n1
.. P2 = 1 atm * (2 * n1 / n1) = 2 atm
2018-04-05 11:51 pm
The pressure will be twice Standard pressure, or 2 atm.
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