a compound made of 5.89g cobalt, 2.80 nitrogen & 9.60g oxygen. determine the emperical formula of this compund?

No. of moles of Co = (5.89 g) / (58.9 g/mol) = 0.1 mol
No. of moles of N = (2.8 g) / (14.0 g/mol) = 0.2 mol
No. of moles of O = (9.60 g) / (16.0 g/mol) = 0.6 mol

Mole ratio Co : N : O = 0.1 : 0.2 : 0.6 = 1 : 2 : 6
Empirical formula = CoN₂O₆