what is the percentage aluminum in AICI3?
回答 (4)
2018-04-04 3:24 am
Mass of 1 mole of AlCl₃ = (27.0 + 35.5×3) g = 133.5 g
Mass of Al in 1 mole of AlCl₃ = 27.0 g
Percentage Al in AlCl₃ = (27.0/133.5) × 100% = 20.2%
Mass of Al in 1 mole of AlCl₃ = 27.0 g
Percentage Al in AlCl₃ = (27.0/133.5) × 100% = 20.2%
2018-04-04 3:25 am
percent aluminum.....
Simply use the molar masses.
26.98g / 133.33g x 100 = 20.24%
Simply use the molar masses.
26.98g / 133.33g x 100 = 20.24%
2018-04-04 3:24 am
by weight/mass?
AlCl₃
atomic mass
Al = 26.98
Cl = 35.45
1 mole of AlCl₃ has 26.98 g of Al and 3•35.45 g of Cl for a total of 133.33 g
so the percentage of Al = 26.98 / 133.33 = 0.202 or 20.2 %
AlCl₃
atomic mass
Al = 26.98
Cl = 35.45
1 mole of AlCl₃ has 26.98 g of Al and 3•35.45 g of Cl for a total of 133.33 g
so the percentage of Al = 26.98 / 133.33 = 0.202 or 20.2 %
2018-04-04 3:24 am
%Al = (molar mass Al / molar mass AlCl3) X 100
(27 g/mol Al / 133 g/mol AlCl3) X 100 = 20.3% Al
(27 g/mol Al / 133 g/mol AlCl3) X 100 = 20.3% Al
收錄日期: 2021-04-24 01:05:33
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