1.設f(x) = x2 - 3x + 4,
求：f(-1) , f(0) , f(1) , f(2)
2.設f(x) = x5 - 3x3 +2x - 8,
求：Df(x) , D2f(x), D3f(x)
感謝大大
基礎微積分問題求解答 有兩題?
2018-03-29 10:40 am
回答 (1)
2018-03-29 12:49 pm
✔ 最佳答案
1.設f(x) = x^2 - 3x + 4, f (-1) = (-1)^2 - 3*(-1) + 4 = 8 ,
f (0) = 0^2 - 3*0 + 4 = 4 ,
f (1) = 1^2 - 3*1 + 4 = 2 ,
f (2) = 2^2 - 3*2 + 4 = 2
2.設f(x) = x^5 - 3x^3 +2x - 8,
Df (x) = 5 x^4 - 9 x^2 + 2 ,
D2f (x) = 20 x^3 - 18 x,
D3f (x) = 60 x^2 - 18
收錄日期: 2021-04-18 18:06:43
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20180329024050AAhHb0r