Really confused, please include how to get there too:)
At what concentration of ammonia is :
A. [Co^+3] = [Co(NH3)6^+3]? Kf=1.00 x 10^23
B. [Ag^+1] = [Ag(NH3)2^+1] Kf=1.70 x 10^7
HELP WITH CHEM!!!!?
2018-03-22 8:28 pm
回答 (1)
2018-03-22 9:31 pm
A.
Co³⁺(aq) + 6NH₃(aq) ⇌ Co(NH₃)₆³⁺(aq) …. Kf = 1.00 × 10²³
Kf = [Co(NH₃)₆³⁺] / ([Co³⁺] [NH₃]⁶) = 1.00 × 10²³
When [Co³⁺] = [Co(NH₃)₆³⁺]:
1 / [NH₃]⁶ = 1.00 × 10²³
[NH₃] = {1 / (1.00 × 10²³)}^(1/6) M = 1.47 × 10⁻⁴ M
====
B.
Ag⁺(aq) + 2NH₃(aq) ⇌ Ag(NH₃)₂⁺(aq) …. Kf = 1.70 × 10⁷
Kf = [Ag(NH₃)₂⁺] / ([Ag⁺] [NH₃]²) = 1.70 × 10⁷
When [Ag⁺] = [Ag(NH₃)₂⁺]:
1 / [NH₃]² = 1.70 × 10⁷
[NH₃] = √{1 / (1.70 × 10⁷)} M = 2.43 × 10⁻⁴ M
Co³⁺(aq) + 6NH₃(aq) ⇌ Co(NH₃)₆³⁺(aq) …. Kf = 1.00 × 10²³
Kf = [Co(NH₃)₆³⁺] / ([Co³⁺] [NH₃]⁶) = 1.00 × 10²³
When [Co³⁺] = [Co(NH₃)₆³⁺]:
1 / [NH₃]⁶ = 1.00 × 10²³
[NH₃] = {1 / (1.00 × 10²³)}^(1/6) M = 1.47 × 10⁻⁴ M
====
B.
Ag⁺(aq) + 2NH₃(aq) ⇌ Ag(NH₃)₂⁺(aq) …. Kf = 1.70 × 10⁷
Kf = [Ag(NH₃)₂⁺] / ([Ag⁺] [NH₃]²) = 1.70 × 10⁷
When [Ag⁺] = [Ag(NH₃)₂⁺]:
1 / [NH₃]² = 1.70 × 10⁷
[NH₃] = √{1 / (1.70 × 10⁷)} M = 2.43 × 10⁻⁴ M
收錄日期: 2021-05-01 22:27:10
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20180322122840AAMLGY6