設π<Θ＜3π/2且sinΘ=-5/13，則sin2Θ=?〗 cos2Θ=? tan2Θ=?
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2018-03-22 5:52 pm
✔ 最佳答案
設π<Θ＜3π/2且SinΘ=－5/13，則Sin2Θ=?〗 Cos2Θ=? Tan2Θ=?Sol
π<Θ＜3π/2且SinΘ=－5/13
CosΘ=－12/13
Sin2Θ=2SinΘCosΘ=120/169
Cos2Θ=Cos^2 Θ－Sin^2 Θ=144/169－25/169=119/169
Tan2Θ=Sin2Θ/Cos2Θ=120/119
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https://hk.answers.yahoo.com/question/index?qid=20180322062915AAxFk7K