Coefficient of Friction?
2018-03-17 6:41 pm
A block of mass m is released on the top of a smooth inclined plane of length x and inclination theta. Horizontal surface is rough. If block comes to rest after moving a distance d on the horizontal surface, then coefficient of friction between block and surface is?
回答 (3)
2018-03-17 7:21 pm
✔ 最佳答案
Refer to the diagram below.Loss in P.E. = m g h = m g x sinθ
Energy to overcome friction = f d = μ m g d
Energy to overcome friction = Loss in P.E.
Coefficient of friction between the block and the surface, μ = x sinθ / d
2018-03-17 6:59 pm
The driving force is mg sin( theta)
The energy gained is mgx * sin(theta)
This goes into work on the horizontal surface mg * coefficient * d
equate the two and simplify
x * sin( theta) = d * coefficient
coefficient = x/d * sin(theta)
The energy gained is mgx * sin(theta)
This goes into work on the horizontal surface mg * coefficient * d
equate the two and simplify
x * sin( theta) = d * coefficient
coefficient = x/d * sin(theta)
2018-03-17 6:55 pm
The potential energy mg*xsinΘ is consumed by the friction loss across the surface:
mg*xsinΘ = mg*µ*d so xsinΘ/d = µ
mg*xsinΘ = mg*µ*d so xsinΘ/d = µ
收錄日期: 2021-05-01 22:25:57
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