i need help on number 71 and 75 thank you?
回答 (2)
71)
f(x) = (5x+4)^(1/3)
g(x) = (1/5)x^3 -4/5
(f.g)(x) = f( g(x) )
= f ( (1/5)x^3 - 4/5)
= (5 ( (1/5)x^3 - 4/5) +4 )^(1/3)
= ( x^3-4+4)^(1/3)
= (x^3)^(1/3)
= x
g( f(x)) = g ( (5x+4)^(1/3) )
= (1/5) ((5x+4)^(1/3))^3 - 4/5
= (1/5) (5x+4) - 4/5
= x + 4/5 - 4/5
= x
75)
f(x) = x^2-4
f(x+h) = (x+h)^2 - 4
f(x+h)= x^2+2xh+h^2 - 4
f(x)+f(h) = x^2-4 + h^2 - 4
= x^2+h^2-8
71) f(x) = ∛(5x + 4) , g(x) = (1/5)x^3 - 4/5
f(g(x)) = ∛[5((1/5)x^3 - 4/5))+ 4] = ∛(x^3 - 4 + 4) = ∛(x^3) = x
g(f(x)) = (1/5) [∛(5x + 4)]^3 - 4/5 = (1/5)(5x + 4) - 4/5 = x + 4/5 - 4/5 = x
▮
75) f(x) = x^2 - 4
f(x + h) = (x + h)^2 - 4 = x^2 + 2xh + h^2 - 4
f(x) + f(h) = x^2 - 4 + h^2 - 4 = x^2 + h^2 - 8
75/
f(x)=x^2-4
f(x+h)=(x+h)^2-4
f(x)+f(h)=x^2-4+h^2-4=...
收錄日期: 2021-04-24 00:58:31
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20180315063719AA2Vyom
檢視 Wayback Machine 備份