What is the standard molar entropy of O2(g) at 25°C?
S°(KClO3, s) = (143.1 J/mol × K).
S°(KCl, s) = (82.6 J/mol × K)?
The change in standard molar entropy, DS°, for the following reaction is 494.6 J/mol × K at 25°C. 2KClO3(s) ⇌ 2KCl(s) + 3O2(g).?
2018-03-14 2:09 pm
回答 (1)
2018-03-14 3:35 pm
✔ 最佳答案
2KClO₃(s) ⇌ 2KCl(s) + 3O₂(g) …… ΔS° = 494.6 J/(mol K)ΔS° of the reaction = 3S°(O₂, g) + 2S°(KCl, s) - 2S°(KClO₃, s)
494.6 J/(mol K) = 3S°(O₂, g) + 2[82.6 J/(mol K)] - 2[143.1 J/(mol K)
Standard molar entropy of O₂(g) at 25°C
= (1/3) (494.6 - 2×82.6 + 2×143.1) J/(mol K)
= 205.2 J/(mol K)
收錄日期: 2021-04-24 00:58:15
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20180314060912AAs46ug