calculate the liters of a 1.90 M NaCl solution to obtain 12.0 moles of NaCl?
回答 (2)
2018-03-08 3:56 pm
Volume
= (No. of moles) / Molarity
= (12.0 mol) / (1.90 mol/L)
= 6.32 L
= (No. of moles) / Molarity
= (12.0 mol) / (1.90 mol/L)
= 6.32 L
2018-03-08 4:16 pm
1.0L of solution contains 1.90 mol NaCl
Volume that contains 12.0 mol NaCl = 12.0mol/L/1.90mol/L *1.0 = 6.32L
Volume that contains 12.0 mol NaCl = 12.0mol/L/1.90mol/L *1.0 = 6.32L
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