A solution contains 0.436 M ammonium iodide and 0.440 M ammonia.
The pH of this solution is what?
The pH of this solution is what?
2018-03-08 3:38 pm
回答 (1)
2018-03-08 4:04 pm
✔ 最佳答案
Kb for NH₃ = 1.8 × 10⁻⁵ In the solution :
[NH₃] = 0.440 M
[NH₄⁺] = [NH₄I] = 0.436 M
NH₃(aq) + H₂O(l) ⇌ NH₄⁺(aq) + OH⁻(aq) …… Kb = 1.8 × 10⁻⁵
pOH = pKb + log([NH₄⁺]/[NH₃]) = -log(1.8 × 10⁻⁵) + log(0.436/0.440) = 4.74
pH = pKa - pOH = 14.00 - 4.74 = 9.26
收錄日期: 2021-05-01 22:23:30
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20180308073809AA9SRcH