The rate constant for this first-order reaction is 0.0300 s–1 at 300 °C.
A--------> Products
Calculate the mass of A remaining after 0.998 min if the initial mass of A is 16.29 g.
Chemistry help please. Reaction question?
2018-03-08 11:17 am
回答 (2)
2018-03-08 12:10 pm
✔ 最佳答案
A → ProductsRate law: Rate = k [A]
Integrated rate law: [A] = [A]ₒ e^(-kt)
Under constant volume: m = mₒ e^(-kt)
After 0.998 min:
Mass, m = (16.29 g) e^[-0.0300 × (0.998 × 60)] = 2.70 g
2018-03-08 12:05 pm
ln[A] = -kt + ln[A]o
0.998 min x 60 sec/min = 59.88 seconds
ln[A] = -0.0300s-1(59.88 seconds) + ln(16.29 g)
ln[A] = -1.79 + 2.79
ln[A] = 1.00
amount of A remaining = 2.72 grams
0.998 min x 60 sec/min = 59.88 seconds
ln[A] = -0.0300s-1(59.88 seconds) + ln(16.29 g)
ln[A] = -1.79 + 2.79
ln[A] = 1.00
amount of A remaining = 2.72 grams
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