✔ 最佳答案
1.
Molar mass of Ca = 40.1 g/mol
Molar mass of Cl₂ = 35. 5×2 g/mol = 71. 0 g/mol
Overall equation: CaCl₂(l) → Ca(s) + Cl₂(g)
Mole ratio Ca : Cl₂ = 1 : 1
No. of moles of Ca = (2 g) / (40.1 g/mol) = 0.0499 mol
No. of moles of Cl₂ = 0.0499 mol
Mass of Cl₂ = (0.0499 mol) × (71.0 g/mol) = 3.54 g
2.
Quantity of electricity passed = It = 2 × (402 × 60) C = 48240 C
1 mole of e⁻ carries 96485 C of electricity.
No. of moles of e⁻ passed = (48240 C) / (96485 C/mol) = 0.5 mol
Cathodic reaction: Al³⁺(l) + 3e⁻ → Al(l)
Mole ratio e⁻ : Al = 3 : 1
No. of moles of Al = (0.5 mol) × (1/3) = 0.5/3 mol
Molar mass of Al = 27.0 g/mol
Mass of Al obtained at the cathode = (0.5/3 mol) × (27.0 g/mol) = 4.5 g