The heat of fusion of water is 6.01 kJ/mol. the heat capacity of liquid water is 75.3 J/mol-K.?
2018-02-23 7:40 am
The heat of fusion of water is 6.01 kJ/mol. the heat capacity of liquid water is 75.3 J/mol-K. The conversion of 50 g of ice at 0.00 degrees celsius to liquid water at 0.00 degrees celsius requires_______kJ of heat?
回答 (1)
2018-02-23 8:56 am
Molar mass of water (H₂O)
= (1.0×2 + 16.0) g/mol
= 18.0 g/mol
No. of moles of water in 50 g of ice
= (50 g) / (18.0 g/mol)
= 2.78 mol
Heat required for the conversion of 50 g of ice at 0.00°C to liquid water at 0.00°C
= (2.78 mol) × (6.01 kJ/mol)
= 16.7 kJ
(The given value of heat capacity of liquid water is redundant.)
= (1.0×2 + 16.0) g/mol
= 18.0 g/mol
No. of moles of water in 50 g of ice
= (50 g) / (18.0 g/mol)
= 2.78 mol
Heat required for the conversion of 50 g of ice at 0.00°C to liquid water at 0.00°C
= (2.78 mol) × (6.01 kJ/mol)
= 16.7 kJ
(The given value of heat capacity of liquid water is redundant.)
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