148.3 mg/mEq
64.5 mg/mEq
37.07 mg/mEq
74.15 mg/mEq
Calculate the milliequivalent weight of Mg(NO3)2.?
2018-02-21 5:40 pm
回答 (3)
2018-02-21 6:00 pm
Molar weight of Mg(NO₃)₂ = (24.3 + 14.0×2 + 16.0×6) g/mol = 148.3 g/mol
Each mole of Mg(NO₃)₂ consists of 1 mole of Mg²⁺ ions and 2 moles of NO₃⁻ ions.
Hence, 1 mole of Mg(NO₃)₂ is equal to 2 eq. of Mg(NO₃)₂.
Equivalent weight of Mg(NO₃)₂ = (148.3 g/mol) × (1 mol / 2 Eq) = 74.15 g/Eq
Milliequivalent weight of Mg(NO₃)₂ = 74.15 g/Eq = 74.15 mg/mEq
The answer: 74.15 mg/mEq
Each mole of Mg(NO₃)₂ consists of 1 mole of Mg²⁺ ions and 2 moles of NO₃⁻ ions.
Hence, 1 mole of Mg(NO₃)₂ is equal to 2 eq. of Mg(NO₃)₂.
Equivalent weight of Mg(NO₃)₂ = (148.3 g/mol) × (1 mol / 2 Eq) = 74.15 g/Eq
Milliequivalent weight of Mg(NO₃)₂ = 74.15 g/Eq = 74.15 mg/mEq
The answer: 74.15 mg/mEq
2018-02-21 7:43 pm
74.15 mg/mEq
2018-02-21 6:33 pm
69
收錄日期: 2021-04-24 01:01:44
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