10 mL
13 mL
80 mL
0.013 mL
What amount of 0.50 mol/L NaOH is required to titrate 10.0 mL of a 2.00 mol/L H2SO4 solution?
2018-02-21 5:23 pm
回答 (1)
2018-02-21 5:31 pm
2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O
2 moles of NaOH react with 1 mole of H₂SO₄.
No. of millimoles of H₂SO₄ reacted = (2.00 mmol/mL) × (10.0 mL) = 20.0 mmol
No. of millimoles of NaOH required = (20.0 mmol) × (2/1) = 40.0 mmol
Volume of NaOH required = (40.0 mmol) / (0.50 mmol/mL) = 80 mL
The answer: 80 mL
2 moles of NaOH react with 1 mole of H₂SO₄.
No. of millimoles of H₂SO₄ reacted = (2.00 mmol/mL) × (10.0 mL) = 20.0 mmol
No. of millimoles of NaOH required = (20.0 mmol) × (2/1) = 40.0 mmol
Volume of NaOH required = (40.0 mmol) / (0.50 mmol/mL) = 80 mL
The answer: 80 mL
收錄日期: 2021-05-01 22:02:52
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