what will the reaction rate be at 49 °C?

Eₐ = 77 kJ mol⁻¹ = 77000 J mol⁻¹
When T₁ = (273 + 27) K = 300 K, k₁ = 0.575 mol L⁻¹ h⁻¹
When T₂ = (273 + 49) K = 322 K, k₂ = ? mol L⁻¹ h⁻¹

A form of Arrhenius equation: ln(k₂/k₁) = (Eₐ/R) [(1/T₁) - (1/T₂)]
k₂/k₁ = e^{(Eₐ/R) [(1/T₁) - (1/T₂)]}
k₂ = k₁ e^{(Eₐ/R) [(1/T₁) - (1/T₂)]}

Rate at 49°C, k₂
= 0.575 × e^{(77000/8.314) [(1/300) - (1/322)]} mol L⁻¹ h⁻¹
= 4.74 mol L⁻¹ h⁻¹