更新1:
(use 2.1 J/g C for the specific heat of ice and 334.4 J/g for the heat of fusion )
a sample of h2o with the mass of 46.0 grams has a temp of -58.0 how many joules of energy are necessary to melt 46.0 grams of ice?
回答 (1)
2018-02-14 11:29 am
Energy needed to raise temperature = m c ΔT
Energy needed to melt a substance = m L
Energy needed to change 46.0 g ice at -58°C to 0°C ice
= (46.0 g) × (2.1 J/g°C) × 58°C
= 5603 J
Energy needed to melt 46.0 g ice at 0°C
= (46.0 g) × (334.4 J/g)
= 15382 J
Total energy necessary
= (5603 + 15382) J
= 21000 J
Energy needed to melt a substance = m L
Energy needed to change 46.0 g ice at -58°C to 0°C ice
= (46.0 g) × (2.1 J/g°C) × 58°C
= 5603 J
Energy needed to melt 46.0 g ice at 0°C
= (46.0 g) × (334.4 J/g)
= 15382 J
Total energy necessary
= (5603 + 15382) J
= 21000 J
收錄日期: 2021-05-01 14:09:37
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20180214024719AADkDBp