A juniper-wood plank measuring 0.24 ft by 1 ft by 12 ft is totally submerged in water. (a) What is its weight? (In lbs) (b) Buoyant force?
回答 (1)
2018-02-12 2:20 pm
juniper wood density :
# dry = 40 lb/ft^3
# wet = 53 lb/ft^3
fresh water density = 62.37 lb/ft^3
plank volume V = 0.24*1*12 = 2.88 ft^3
# dry weight = 2.88*40 = 117 lb
# wet weight = 2.88*53 = 153 lb
buoyant force Fb = 2.88*62.37 = 180 lb
# dry = 40 lb/ft^3
# wet = 53 lb/ft^3
fresh water density = 62.37 lb/ft^3
plank volume V = 0.24*1*12 = 2.88 ft^3
# dry weight = 2.88*40 = 117 lb
# wet weight = 2.88*53 = 153 lb
buoyant force Fb = 2.88*62.37 = 180 lb
收錄日期: 2021-05-01 22:29:28
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20180212053230AAM97je