The radius of an atom of rhodium (Rh) is about 1.3 Å.
(a)
(i)Express this distance in nano meter. (nm).
(ii) Express this distance in pico meters (pm).
(b) How many rhodium (Rh) atoms would have be lined up to span 1.0 mm?
(c) If the atom is assumed to be sphere, what is the voulme in cm^3 of a single rhodium (Rh) atom? (answer in cm^3)
BASIC CHEMISTRY!!!?
2018-02-06 10:22 am
回答 (1)
2018-02-06 11:21 am
(a)
(i)
1 m = 1 × 10¹⁰ Å = 1 × 10⁹ nm
Radius of Rh atom = (1.3 Å) × [(1 × 10⁹ nm) / (1 × 10¹⁰ Å)] = 0.13 nm
(ii)
1 m = 1 × 10¹⁰ Å = 1 × 10¹² pm
Radius of Rh atom = (1.3 Å) × [(1 × 10¹² pm) / (1 × 10¹⁰ Å)] = 130 pm
(b)
1 m = 1 × 10¹⁰ Å = 1 × 10³ mm
Diameter of Rh atom = 2 × (1.3 Å) × [(1 × 10³ mm) / (1 × 10¹⁰ Å)] = 2.6 × 10⁻⁷ mm
No. of Rh atoms = (1.0 mm) / (2.6 × 10⁻⁷ mm/atom) = 3.8 × 10⁶ atoms (to 2 sig. fig.)
(c)
1 m = 1 × 10¹⁰ Å = 1 × 10² cm
Diameter of Rh atom = (1.3 Å) × [(1 × 10² cm) / (1 × 10¹⁰ Å)] = 1.3 × 10⁻⁸ cm
Volume of Rh atoms = (4/3) × π × (1.3 × 10⁻⁸ cm)³ = (4/3) × 3.14 × (1.3 × 10⁻⁸ cm)³ = 9.2 × 10⁻²⁴ cm³
(to 2 sig. fig.)
(i)
1 m = 1 × 10¹⁰ Å = 1 × 10⁹ nm
Radius of Rh atom = (1.3 Å) × [(1 × 10⁹ nm) / (1 × 10¹⁰ Å)] = 0.13 nm
(ii)
1 m = 1 × 10¹⁰ Å = 1 × 10¹² pm
Radius of Rh atom = (1.3 Å) × [(1 × 10¹² pm) / (1 × 10¹⁰ Å)] = 130 pm
(b)
1 m = 1 × 10¹⁰ Å = 1 × 10³ mm
Diameter of Rh atom = 2 × (1.3 Å) × [(1 × 10³ mm) / (1 × 10¹⁰ Å)] = 2.6 × 10⁻⁷ mm
No. of Rh atoms = (1.0 mm) / (2.6 × 10⁻⁷ mm/atom) = 3.8 × 10⁶ atoms (to 2 sig. fig.)
(c)
1 m = 1 × 10¹⁰ Å = 1 × 10² cm
Diameter of Rh atom = (1.3 Å) × [(1 × 10² cm) / (1 × 10¹⁰ Å)] = 1.3 × 10⁻⁸ cm
Volume of Rh atoms = (4/3) × π × (1.3 × 10⁻⁸ cm)³ = (4/3) × 3.14 × (1.3 × 10⁻⁸ cm)³ = 9.2 × 10⁻²⁴ cm³
(to 2 sig. fig.)
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