Calculate the volume of a 0.106 M CuSO4 solution that would react with 7.19 g of zinc. Enter your answer in scientific notation.?
回答 (1)
2018-02-06 1:15 am
Molar mass of Zn = 65.4 g/mol
No. of moles of Zn reacted = (7.19 g) / (65.4 g/mol) = 0.110 mol
Equation for the reaction :
Zn(s) + CuSO₄(aq) → ZnSO₄(aq) + Cu(s)
Each mole Zn reacts with 1 mole CuSO₄.
No. of moles of CuSO₄ needed = (0.110 mol) × 1 = 0.110 mol
Volume of CuSO₄ needed = (0.110 mol) / (0.106 mol/L) = 1.04 L = 1.04 × 10³ mL
No. of moles of Zn reacted = (7.19 g) / (65.4 g/mol) = 0.110 mol
Equation for the reaction :
Zn(s) + CuSO₄(aq) → ZnSO₄(aq) + Cu(s)
Each mole Zn reacts with 1 mole CuSO₄.
No. of moles of CuSO₄ needed = (0.110 mol) × 1 = 0.110 mol
Volume of CuSO₄ needed = (0.110 mol) / (0.106 mol/L) = 1.04 L = 1.04 × 10³ mL
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