What is the answer to this Maths q.?
回答 (7)
2018-02-04 10:51 pm
Be careful with your notation. As written the division takes precedence, so your expression would equivalent to:
(26/4) + √3
= 13/2 + √3
= 6.5 + √3
However, that's obviously not what you meant because it doesn't simplify to a form with integers values of a and b.
What you intended to write was:
26/(4 + √3)
Do you see why the parentheses are necessary?
Okay, from there, just multiply top and bottom by the conjugate of 4 + √3 --> namely 4 - √3
26(4 - √3)
--------------------
(4 + √3)(4 - √3)
26(4 - √3)
---------------
16 - (√3)²
26(4 - √3)
---------------
16 - 3
26(4 - √3)
---------------
..... 13
2(4 - √3)
Answer:
8 - 2√3
a = 8, b = -2
(26/4) + √3
= 13/2 + √3
= 6.5 + √3
However, that's obviously not what you meant because it doesn't simplify to a form with integers values of a and b.
What you intended to write was:
26/(4 + √3)
Do you see why the parentheses are necessary?
Okay, from there, just multiply top and bottom by the conjugate of 4 + √3 --> namely 4 - √3
26(4 - √3)
--------------------
(4 + √3)(4 - √3)
26(4 - √3)
---------------
16 - (√3)²
26(4 - √3)
---------------
16 - 3
26(4 - √3)
---------------
..... 13
2(4 - √3)
Answer:
8 - 2√3
a = 8, b = -2
2018-02-04 10:47 pm
26/4+√3 = 13/2+√3 = a+b√3 with a=13/2 and b=1.
Unfortunately, a is not an integer.
Unfortunately, a is not an integer.
2018-02-04 10:37 pm
Cannot be expressed with integer coefficients as presented. However if parentheses are added such that the term is:
26/(4+√3)
then the denominator can be rationalized by multiplying by the conjugate of the denominator:
26(4-√3)/[(4+√3)(4-√3)]
= (104 - 26√3)/(16-3)
= 104/13 - 26√3/13
= 8 - 2√3
26/(4+√3)
then the denominator can be rationalized by multiplying by the conjugate of the denominator:
26(4-√3)/[(4+√3)(4-√3)]
= (104 - 26√3)/(16-3)
= 104/13 - 26√3/13
= 8 - 2√3
2018-02-04 10:29 pm
26 ........4 - √3
--------- x ---------
4 + √3 ... 4 - √3
104 - 26√3
---------------
13
8 -2√3
a=8
b=-2
--------- x ---------
4 + √3 ... 4 - √3
104 - 26√3
---------------
13
8 -2√3
a=8
b=-2
2018-02-05 12:21 pm
QuickMath will automatically answer the most common problems in algebra, equations and calculus faced by high-school and college students. The algebra section allows you to expand, factor or simplify virtually any expression you choose.
2018-02-05 5:20 am
26/(4 + √3)
= 26(4 - √3)/(4 + √3)(4 - √3)
= 2(4 - √3)
= 26(4 - √3)/(4 + √3)(4 - √3)
= 2(4 - √3)
2018-02-04 10:59 pm
It's already in that form.
If you meant 26/(4 + √3), then
26/(4 + √3) * (4 - √3)/(4 - √3) =
(104 - 26√3)/(16 - 3) =
(104/7 - 26√3)/13 =
104/13 - 26√3/13 =
8 - 2√3
If you meant 26/(4 + √3), then
26/(4 + √3) * (4 - √3)/(4 - √3) =
(104 - 26√3)/(16 - 3) =
(104/7 - 26√3)/13 =
104/13 - 26√3/13 =
8 - 2√3
2018-02-04 11:17 pm
Could it be that should actually be shown as :-
26 / [ 4 + √3 ] ?
If so , this becomes :-
26 [ 4 - √ 3 ]
----------------------
[ 4 + √3 ] [ 4 - √ 3 ]
26 [ 4 - √ 3 ]
----------------------
16 - 9
26 [ 4 - √ 3 ]
----------------------
7
(26/7) [ 4 - √ 3 ]
26 / [ 4 + √3 ] ?
If so , this becomes :-
26 [ 4 - √ 3 ]
----------------------
[ 4 + √3 ] [ 4 - √ 3 ]
26 [ 4 - √ 3 ]
----------------------
16 - 9
26 [ 4 - √ 3 ]
----------------------
7
(26/7) [ 4 - √ 3 ]
收錄日期: 2021-04-24 00:55:15
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20180204142623AAFK5Bq