Report your final answer to two decimal places.
b. What is the energy absorbed by the water in calories? Show your work and report your final answer
to one decimal place.
c. What is this energy equal to if you use the units of dietary Calories?
97.90 mL of water was heated from 2.0°C to 25.0°C. The density of water is 1.00 g/mL. What is the mass of the water used?
2018-01-26 8:45 am
回答 (1)
2018-01-26 10:01 am
✔ 最佳答案
a.Mass of water = (97.90 mL) × (1.00 g/mL) = 97.90 g
b.
Mass, m = 97.90 g
Heat capacity, c = 1 cal/g°C
Change in temperature, ΔT = (25.0 - 2.0)°C = 23.0°C
Energy absorbed = m c ΔT = (97.90 g) × (1 cal/g°C) × (23.0°C) = 2251.7 cal
c.
Heat absorbed = (2251.7 cal) × (1 dietary Calories / 1000 cal) = 2.2517 dietary Calories
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