Ni2+ + 2e- →Ni (E°= -0.28 V)
Zn2+ + 2e- →Zn (E°= -0.76 V)
I need to write the overall reaction. Any help is appreciated @_@
Overall reaction?
2018-01-24 1:53 pm
回答 (2)
2018-01-24 2:00 pm
✔ 最佳答案
Ni²⁺(aq) + 2e⁻ → Ni(s) …… E° = -0.28 VZn(s) → Zn²⁺(aq) + 2e⁻ …… E° = -(-0.76 V) = +0.76 V
Add the above two half equations, and cancel 2e⁻ on the both sides.
The overall equation is :
Zn(s) + Ni²⁺(aq) → Zn²⁺(aq) + Ni(s) …… E°(cell) = -0.28 + 0.76 V = +0.48 V
2018-01-24 1:57 pm
One get turned around such that the electrons cancel out. The answer with a positive potential is:
Zn + Ni+2 --> Ni + Zn+2 and the potential is 0.76 - 0.28 V or 0.48
Zn + Ni+2 --> Ni + Zn+2 and the potential is 0.76 - 0.28 V or 0.48
收錄日期: 2021-04-24 01:00:04
原文連結 [永久失效]:
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