Na= 23, C= 12, O= 16.
Thank you so much for your help!
What mass of sodium ethanedioate, Na₂C₂O₄, must be weighed out to obtain 600cm³ of a solution with a concentration of 0.80moldm-³?
2018-01-23 9:21 am
回答 (2)
2018-01-23 11:08 am
No. of moles of Na₂C₂O₄ in the solution = (0.80 mol dm⁻³) × (600/1000 dm³) = 0.48 mol
Molar mass of Na₂C₂O₄ = (23×2 + 12×2 + 16×4) /mol = 134 g/mol
Mass of Na₂C₂O₄ must be weighed out = (0.48 mol) × (134 g/mol) = 64 g (to 2 sig. fig.)
Molar mass of Na₂C₂O₄ = (23×2 + 12×2 + 16×4) /mol = 134 g/mol
Mass of Na₂C₂O₄ must be weighed out = (0.48 mol) × (134 g/mol) = 64 g (to 2 sig. fig.)
2018-01-23 9:24 am
134g X 0.6 X 0.8 <<<< use a calculator
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