physics circuits question pls help?
回答 (5)
2018-01-20 1:01 am
(a)
Ohm's law: V = IR
Potential difference across the 1.50 Ω resistor
= 0.24 × 15 V
= 3.6 V
(b)
Potential difference across the 4.0 Ω resistor :
(6.0 - 3.6) V = I₁ × (4.0 Ω)
I₁ = 0.6 A
(c)
I₂ + (0.24 A) = 0.6 A
I₂ = 0.36 A
Potential difference across the R resistor :
3.6 V = (0.36 A) × R
R = 10 Ω
Ohm's law: V = IR
Potential difference across the 1.50 Ω resistor
= 0.24 × 15 V
= 3.6 V
(b)
Potential difference across the 4.0 Ω resistor :
(6.0 - 3.6) V = I₁ × (4.0 Ω)
I₁ = 0.6 A
(c)
I₂ + (0.24 A) = 0.6 A
I₂ = 0.36 A
Potential difference across the R resistor :
3.6 V = (0.36 A) × R
R = 10 Ω
2018-01-20 1:27 pm
V15 = VR = 0.24*15 = 3.6 V
V4 = V-V15 = 6.0-3.6 = 2.4 V
I1 = V4/R4 = 2.4/4 = 0.6 A
I2 = I1-0.24 = 0.6-0.24 = 0.36 A
R = V15/I2 = 3.6/0.36 = 10.0 ohm
...therefore :
a) = 3.6 V
b) = 0.6 A
c) = 0.36 A ; 10.0 ohm
V4 = V-V15 = 6.0-3.6 = 2.4 V
I1 = V4/R4 = 2.4/4 = 0.6 A
I2 = I1-0.24 = 0.6-0.24 = 0.36 A
R = V15/I2 = 3.6/0.36 = 10.0 ohm
...therefore :
a) = 3.6 V
b) = 0.6 A
c) = 0.36 A ; 10.0 ohm
2018-01-20 1:11 am
a) 0.24a*15ohms = 3.6v
b) volts across 4 ohms = (6 - 3.6) volts = 2.4 volts
Current in 4 ohms = 2.4v/4ohms = 0.6 amps
c) I2 = (0.6 - 0.24) amps = 0.36 amps
R = 3.6v/0.36a = 10 ohms
b) volts across 4 ohms = (6 - 3.6) volts = 2.4 volts
Current in 4 ohms = 2.4v/4ohms = 0.6 amps
c) I2 = (0.6 - 0.24) amps = 0.36 amps
R = 3.6v/0.36a = 10 ohms
2018-01-20 1:03 am
(a) V = (0.24 A) *(15 Ω)= 3.6 V
(b) Voltage across 4.0Ω will be 6.0V - 3.6V = 2.4 V
I₁ = (2.4 V) / 4.0Ω = 0.6 A
(c) I₂=I₁ - (0.24 A) = 0.60 - 0.24 = 0.36 A
R = (3.6 V)/(0.36 A) = 10 Ω
(b) Voltage across 4.0Ω will be 6.0V - 3.6V = 2.4 V
I₁ = (2.4 V) / 4.0Ω = 0.6 A
(c) I₂=I₁ - (0.24 A) = 0.60 - 0.24 = 0.36 A
R = (3.6 V)/(0.36 A) = 10 Ω
2018-01-20 1:02 am
a) E = IR = 0.24 amps x 15 Ω = 3.6 volts
b) voltage across 4Ω is 6v – 3.6v = 2.4 volts
current through 4Ω:
I = E/R = 2.4 / 4 = 0.6 amps
c) current through R is the difference, 0.6 – 0.24 = 0.36 amps
voltage across R is the same as that across 15Ω, 3.6 volts
R = E/I = 3.6 volts / 0.36 amps = 10 Ω
As a check, two R's in parallel are 10•15/(10+15) = 150/25 = 6 ohms
total circuit R is then 6 + 4 = 10 ohms
total current = 6/10 = 0.6 amps
b) voltage across 4Ω is 6v – 3.6v = 2.4 volts
current through 4Ω:
I = E/R = 2.4 / 4 = 0.6 amps
c) current through R is the difference, 0.6 – 0.24 = 0.36 amps
voltage across R is the same as that across 15Ω, 3.6 volts
R = E/I = 3.6 volts / 0.36 amps = 10 Ω
As a check, two R's in parallel are 10•15/(10+15) = 150/25 = 6 ohms
total circuit R is then 6 + 4 = 10 ohms
total current = 6/10 = 0.6 amps
收錄日期: 2021-04-18 18:03:11
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