A 4.75 g of Sodium sulfate that has been combined with water create a solution with a volume of 50 mL. Find concentration of this solution.?
回答 (1)
2018-01-19 2:51 pm
Molar mass of Na₂SO₄ = (23.0×2 + 32.1 + 16.0×4) g/mol = 142.1 g/mol
No. of moles of Na₂SO₄ = (4.75 g) / (142.1 g/mol) = 0.003343 mol
Volume of solution = (50 mL) × (1 L / 1000 mL) = 0.05 L
Concentration = (0.003343 mol) / (0.05 L) = 0.0669 M
No. of moles of Na₂SO₄ = (4.75 g) / (142.1 g/mol) = 0.003343 mol
Volume of solution = (50 mL) × (1 L / 1000 mL) = 0.05 L
Concentration = (0.003343 mol) / (0.05 L) = 0.0669 M
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