A student follows the procedure for this experiment and burns a peanut. The peanut weighed 0.780 g before combustion and 0.054 g after combustion. The temperature change of an aluminum can filled with 200 mL of water was 15.3 C (Density of water = 1.00 g/mL)
1. Calculate the amount of energy released (Cal) when the peanut was burned.
2. Calculate the amount of energy per gram of burned nut (Cal/g).
3. Calculate the amount of energy per gram of burned nut (kJ/g).
Chemistry help?
2018-01-17 12:44 pm
回答 (1)
2018-01-17 1:07 pm
✔ 最佳答案
1.The amount of energy released when the peanut was burned
= The amount of energy absorbed by the 200 mL of water
= m c ΔT
= [(200 mL) × (1.00 g/mL)] × (1 cal/g°C) × (15.3°C)
= 3060 cal (or 3.06 kcal)
2.
The amount of energy per gram of burned nut
= (3060 cal) / [(0.780 - 0.054) g]
= 4210 cal/g (or 4.21 kcal/g)
3.
1 cal = 4.283 J
Hence, the amount of energy per gram of burned nut
= (4210 cal/g) × (4.184 J/g)
= 17600 J/g
= 17.6 kJ/g
收錄日期: 2021-04-24 00:54:04
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