MATH HELP PLZ?!? One Question!?

A. When (x, y) = (3, -1): -2x + y = -2(3) + (-1) = -7 < -4 (False)

B. When (x, y) = (1, -2): -2x + y = -2(1) + (-2) = -4 (True)

C. When (x, y) = (-1, 1): -2x + y = -2(-1) + (1) = 3 > -4 (True)

D. When (x, y) = (0, 1): -2x + y = -2(0) + (1) = 1 > -4 (True)

E. When (x, y) = (0, -5): -2x + y = -2(0) + (-5) = -5 < -4 (False)

The answers: B. (1, −2), C. (−1, 1) and D. (0, 1)

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The ordered pairs which are solutions to the inequality
−2x + y ≥ −4
Answer choices:
B. (1, −2)
C. (−1, 1)
D. (0, 1)

A) -2(3) + (-1) = -6 + (-1) = -7. No.

B) -2(1) + (-2) = -2 + (-2) = -4. Yes.

C) -2(-1) + 1 = 2 + 1 = 3. Yes.

D) -2(0) + 1 = 0 + 1 = 1. Yes.

E) -2(0) + (-5) = 0 + (-5) = -5. No.

mathway.com

im too lazy to do it, but what you should do is substitute in each ordered pair into the equation and see which one comes out true. (this is a good test taking tip when given multiple choice)
for example: test answer choice A:
-2(3)+(-1)> -4
-6-1>-4
-7 is not greater than -4, so you know that A is not the right answer