sinx=cosx at x= pi/4
So then you take the integral from 0 to pi/4 of cosx-sinx dx and then from pi/4 to pi of sinx-cosx dx right?
Find the area between y=sinx and y=cosx on [0, pi].?
2018-01-17 6:40 am
回答 (2)
2018-01-17 7:21 am
✔ 最佳答案
On [0, π], the curves y = sinx and y = cosx meet at x = π/4Then, the area between the two curves on [0, π] is the sum of the integral from 0 to π/4 of (cosx - sinx) dx and the integral from π/4 to π of (sinx - cosx) dx.
The calculation is shown below :
2018-01-17 6:56 am
Yes , it's OK
收錄日期: 2021-04-24 00:54:05
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https://hk.answers.yahoo.com/question/index?qid=20180116224025AA8lp7s