With th empirical formula of this compound, for 1 mol of elemnt A and 2.52 mol for element B, do I round off the 2.52 to 2 or 3? AB2 or AB3?
回答 (2)
2018-01-13 5:41 pm
Mole ratio A : B
= 1 : 2.52
= 1×2 : 2.52×2
= 2 : 5.04
≈ 2 : 5
Then, the empirical formula = A₂B₅
= 1 : 2.52
= 1×2 : 2.52×2
= 2 : 5.04
≈ 2 : 5
Then, the empirical formula = A₂B₅
2018-01-13 10:15 pm
you currently have this ration
.. 1 A to 2.52 B
if you double both
.. 2 A to 5.04 B
now you can round off
.. A2B5
.. 1 A to 2.52 B
if you double both
.. 2 A to 5.04 B
now you can round off
.. A2B5
收錄日期: 2021-04-18 18:02:33
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