Solve: 1/3(x-5)+2/15(x-1)=1/5(x+3)?

(1/3)(x - 5) + (2/15)(x - 1) = (1/5)(x + 3)
[(1/3)(x - 5) + (2/15)(x - 1)] * 15 = (1/5)(x + 3) *15
5(x - 5) + 2(x - 1) = 3(x + 3)
5x - 25 + 2x - 2 = 3x + 9
4x = 36
x = 9

5 x - 25 + 2x - 2 = 3x + 9
4x = 36
x = 9

1/3(x-5)+2/15(x-1)=1/5(x+3)

Multiply each term by 15:
5(x-5) +2(x-1) = 3(x+3)

Expand:
5x -25 +2x -2 = 3x +9

Collect x to left, number to right:
4x = 36

Divide all terms by 4
x = 9

1/3(x-5)+2/15(x-1)=1/5(x+3)
15[1/3(x-5)+2/15(x-1)=1/5(x+3)]
5(x - 5) + 2(x - 1) = 3(x + 3)
5x - 25 + 2x - 2 = 3x + 9
7x - 27 = 3x + 9
4x = 36
x = 9

1/3(x - 5) + 2/15(x - 1) = 1/5(x + 3)
5(x - 5) + 2(x - 1) = 3(x + 3)
7x - 27 = 3x + 9
4x = 36
x = 9

(1/3)(x-5)+(2/15)(x-1) = (1/5)(x+3)
multiply both sides by 15
5(x-5) + 2(x-1) = 3(x+3)

5x-25 + 2x - 2 = 3x + 9
7x-27 = 3x+9
7x-3x = 9+27
4x=36
x=9