✔ 最佳答案
For k[NO₂] = -d[NO₂]/dt, i.e.
-d[NO₂]/dt = k[NO₂]
This is the differential form of a FIRST-order reaction.
For [NO₂] = [NO₂]ₒ - kt, i.e.
[NO₂]ₒ - [NO₂] = kt
This is the integrated form of a ZERO-order reaction.
For [NO₂] = 1/[kt + (1/[NO₂]ₒ)], i.e.
kt + (1/[NO₂]ₒ) = 1/[NO₂]
(1/[NO₂]) - (1/[NO₂]ₒ) = kt
This is the integrated from of a SECOND-order reaction.
For -d[NO₂]/dt = k[NO₂]²
This is the differential from of a SECOND-order reaction.
For k[NO₂]² = d[NO]/dt, i.e.
d[NO]/dt = k[NO₂]²
This is the differential from of a SECOND-order reaction.
The three answers :
[NO₂] = 1/[kt + (1/[NO₂]ₒ)]
-d[NO₂]/dt = k[NO₂]²
k[NO₂]² = d[NO]/dt
