please help me with a physics problem?

👨🏻‍🏫 學術台物理學

[匿名]

2018-01-09 11:09 am

A CD-ROM drive in a computer spins the 12-cm-diameter disks at 8300 rpm...how do I find the period in seconds?

更新1:

how about if I wanted to find speed of a speck of dust on the outside edge of this disk?

回答 (3)

不用客氣

2018-01-09 11:15 am

Frequency = 8300/min = 8300/(60 s)

Period = 1/Frequency = (60 s)/8300 = 0.0072289 s ≈ 0.0072 s (to 2 sig. fig.)

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Mr. Smartypants

2018-01-09 11:14 am

Is this a trick question? If it spins at 8300 rpm, one revolution takes 1/8300 of a second. I get 1.205 * 10^-4. That's 0.0001205.

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[匿名]

2018-01-09 11:18 am

divide 8300 / 60 which is the amount of second in a minute?

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