After balancing the following reaction in basic solution, how many electrons have been transferred?

Reduction half-equation: MnO₄⁻ + 2H₂O + 3e⁻ → MnO₂ + 4OH⁻ …… [1]
Oxidation half-equation: 2I⁻ → I₂ + 2e⁻ …… [2]

[1]×2 + [2]×3, and cancel 6e⁻ on the both sides, the overall equation is :
2MnO₄⁻ + 6I⁻ + 6H₂O → 2MnO₂ + 3I₂ + 8OH⁻

6e⁻ have been cancelled, and thus 6 electrons have been transferred.

The answer: A: 6

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