4. A 100 kg box is set into motion down a rough incline from rest. A constant horizontal force F = 20 N.?

2018-01-07 10:44 pm
更新1:

4. A 100 kg box is set into motion down a rough incline from rest. A constant horizontal force F = 20 N. If the box slides down a distance of 5 m, how much work done by the applied force F?

更新2:

a. 50 J b. 50 J c. 87 J d. 87 J I'm not sure if it's M*g*sin(theta) or M*g*Cos(theta) to find the answer

更新3:

theta = 30 degree

回答 (1)

2018-01-08 12:27 am
The component of F along the plane and the motion are opposite in direction.
Hence, F = 20 N and s = -5 m

Work done by the applied force, F
= F s cosθ
= 20 × (-5) × cos30.0° J
= -87 J

The answer: d. -87J


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