Can someone help me do my titration calculations homework?

[匿名]

2018-01-07 9:24 pm

This is the question - "It took 50 cm3 sulphuric acid (H2SO4) to neutralise a bottle of sodium hydroxide. How much HCl would be required to neutralise the bottle of Sodium Hydroxide if the concentration of HCl was the same as the Sulphuric Acid?"
Thankyou

回答 (1)

不用客氣

2018-01-07 11:35 pm

✔ 最佳答案

H₂SO₄ is a diprotic acid (dibasic acid). Each mole of H₂SO₄ dissociates in aqueous solution to give 2 moles of hydrogen ions.
HCl is a monobasic acid (monobasic acid). Each mole of HCl dissociates in aqueous solution to give 1 mole of hydrogen ions.

For H₂SO₄ and HCl with the same concentration, the amount of H⁺ ions given by H₂SO₄ is twice of the amount of H⁺ given by HCl. In other words, the volume of HCl needed in neutralization would be twice of that of H₂SO₄ when the two acids are with the same concentration.

Hence, HCl required = (50 cm³) × 2 = 100 cm³

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