A shopper pushes a 5.32kg cart with ab12.7N?
2018-01-05 5:46 pm
A shopper pushes a 5.32kg cart with ab12.7N force at a -28.7degrees below the horizontal. A friction dove od 8.33N pushes back against the motion. What is the acceleration of the cart?
回答 (3)
2018-01-05 8:28 pm
✔ 最佳答案
F = (12.7 cos28.7° - 8.33) Nm = 5.32 kg
F = ma
a = F/m = (12.7 cos28.7° - 8.33)/5.32 m/s² = 0.528 m/s²
2018-01-05 8:28 pm
A friction dove od 8.33N ??
what does this mean?
what does this mean?
2018-01-05 6:02 pm
the cart doesn't have engine to accelerate
收錄日期: 2021-04-18 18:03:41
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20180105094615AANQtcw