A container of 20cm height is half filled with glycerin and half filled with water calculate the liquid pressure at the bottom of container?

Pressure exerted by a liquid = dgh, where
d is the density of the liquid in kg/m²;
g is the gravitation acceleration 9.81 m/s²; and
h is depth of the liquid in m.

Liquid pressure at the bottom of the container
= (Liquid pressure exerted by the glycerin) + (Liquid pressure exerted by the water)
= [(1260 kg/m³) × (9.81 m/s²) × (0.20/2 m)] + [(1000 kg/m³) × (9.81 m/s²) × (0.20/2 m)]
= 2220 N/m²
= 2.22 kN/m²
= 2.22 kPa

Use the following equation to determine the pressure in N/m^2.

Pressure = Density * g * height

Since the unit of density is kg/m^2, the height must be in meters. For each liquid, the height is 0.1 meter.

P1 = 1260 * 9.8 * 0.1 = 1,234.8 N/m^2
P2 = 1000 * 9.8 * 0.1 = 980 N/m^2
Total pressure = 2,214.8 N/m^2