if the half of an radionuclide is 5 days , if the initial activity was 100 M Bq on the 5th day of the month what will be its activity on the?
2017-12-31 10:11 am
if the half of an radionuclide is 5 days , if the initial activity was 100 Mbq on the 5th day of the month what will be its activity on the 15th day of the month ?
回答 (4)
2017-12-31 10:51 am
✔ 最佳答案
No. of days = (15 - 5) days = 10 daysNo. of half-lives = (10 day) / (5 days/half-life) = 2 half-lives
Activity = (100 Mbq) × (1/2)² = 25 Mbq
2017-12-31 11:17 am
After 10 days, the activity will be reduced by a factor of 4, so it should be 25 Mbq
2017-12-31 10:12 am
25Mbq
2017-12-31 10:12 am
no
收錄日期: 2021-04-18 18:00:11
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