Math help please?
回答 (3)
2017-12-27 1:42 am
1296 = 2⁴ × 3⁴
Hence, 1298 = 6⁴ = 36² = 1296¹
There are 3 pairs of integers (a, b) satisfy the equation aᵇ = 1296, i.e.
(6, 4), (36, 2) and (1296, 1)
Hence, 1298 = 6⁴ = 36² = 1296¹
There are 3 pairs of integers (a, b) satisfy the equation aᵇ = 1296, i.e.
(6, 4), (36, 2) and (1296, 1)
2017-12-27 1:43 am
1296 = 6^4
1296 = (−6)^4
1296 = 6^(2*2) = (6^2)^2 = 36^2
1296 = (−36)^2
1296 = 1296^1
5 integer solutions: (6,4), (−6,4), (36,2), (−36,2), (1296,1)
2017-12-27 3:03 am
You weren't the only one asking this. https://answers.yahoo.com/question/index?qid=20171224020921AAd5mU2
收錄日期: 2021-04-18 18:00:47
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20171226173306AAuGogq