Can someone help me with Chemistry concentration question?

(Actually, CuCl(aq) and Cu₂SO₄(aq) do not exist.)

Each mole of CuCl contains 1 mole of Cu⁺ ions.
No. of moles of Cu⁺ ions in CuCl = No. of moles of CuCl = (0.35 mol/L) × (65.0/1000 L) = 0.02275 mol

Each mole of Cu₂SO₄ contains 2 moles of Cu⁺ ions.
No. of moles of Cu⁺ ions in Cu₂SO₄ = No. of moles of Cu₂SO₄ × 2 = (0.15 mol/L) × (45.0/1000 L) × 2 = 0.0135 mol

Volume of the final solution = (65.0 + 45.0) mL = 110.0 mL = 0.110 L
Final Cu⁺ concentration = [(0.02275 + 0.0135) mol] / (0.110 L) = 0.330 M

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