I've already attempted to do this question multiple times and my (online) teacher said I have the work right but it's just my answer that's wrong. I kept re-calculating it and I still got the same answer (g = 3.37 x 10^-12 N/kg)
Here is the question and the work I did:
Mercury has a mass of 3.30×1023 kg and a radius of 2.44×106 m. Find Mercury’s gravitational field strength. Show your work (formula, substitution, and answer (rounded correctly and with the appropriate unit)).
g = Gm / r^2
G= 6.67 x 10^-11 Nm2 / kg2
m = 3.30 × 1023 kg
r = 2.44 × 106 m
g = Gm / r2
g = (6.67 x 10^-11 Nm2 / kg2) (3.30 × 1023 kg) / (2.44 × 106 m)2
Thank you to anyone who responds!!
Physics Help?
2017-12-19 10:32 pm
回答 (1)
2017-12-20 1:00 am
If you do the math in your last line, you get 3.70 m/s²
It's just arithmetic. if you don't know how to use a calculator, get someone to help you. I can't from here, as I don't know what kind you have.
PS: please learn proper use of exponents. Your last line should be:
g = (6.67 x 10^-11 Nm^2 / kg^2) (3.30 × 10^23 kg) / (2.44 × 10^6 m)^2
improper terminology will just add to your problems and many will not even attempt to answer your questions if they see such errors.
another good terminology is:
g = (6.67e-11 Nm²/kg²) (3.30e23 kg) / (2.44e6 m)²
It's just arithmetic. if you don't know how to use a calculator, get someone to help you. I can't from here, as I don't know what kind you have.
PS: please learn proper use of exponents. Your last line should be:
g = (6.67 x 10^-11 Nm^2 / kg^2) (3.30 × 10^23 kg) / (2.44 × 10^6 m)^2
improper terminology will just add to your problems and many will not even attempt to answer your questions if they see such errors.
another good terminology is:
g = (6.67e-11 Nm²/kg²) (3.30e23 kg) / (2.44e6 m)²
收錄日期: 2021-05-01 21:59:54
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20171219143244AAOQmrt