How many moles are in 6.84g of Fe2O3?
回答 (2)
2017-12-19 12:05 am
Molar mass of Fe₂O₃ = (55.85×2 + 16.00×3) g/mol = 159.70 g/mol
No. of moles of Fe₂O₃ = (6.84 g) / (159.70 g/mol) = 0.0428 mol
No. of moles of Fe₂O₃ = (6.84 g) / (159.70 g/mol) = 0.0428 mol
2017-12-19 12:07 am
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