Calculate the number of atoms of oxygen in 93 grams of so3.?
回答 (1)
2017-12-18 9:44 pm
Molar mass of SO₃ = (32.1 + 16.0×3) g/mol = 80.1 g/mol
No. of moles of SO₃ = (93 g) / (80.1 g/mol) = 1.16 mol
Avogadro constant = 6.022 × 10²³ /mol
and each mole of SO₃ contains 3 moles of O atoms.
No. of O atoms = (1.16 mol) × (6.022 × 10²³ molecules/mol) × (3 O atoms/molecule) = 2.10 × 10²⁴ O atoms
No. of moles of SO₃ = (93 g) / (80.1 g/mol) = 1.16 mol
Avogadro constant = 6.022 × 10²³ /mol
and each mole of SO₃ contains 3 moles of O atoms.
No. of O atoms = (1.16 mol) × (6.022 × 10²³ molecules/mol) × (3 O atoms/molecule) = 2.10 × 10²⁴ O atoms
收錄日期: 2021-04-18 18:04:39
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20171218125651AAj1WOq