2Na (s) + 2 H2O (l) → 2NaOH (aq) + H2 (g) If 4.52 moles of Na react with an excess of water, how many grams of H2 are formed?

2Na(s) + 2H₂O(l) → 2NaOH(aq) + H₂(g)
Mole ratio Na : H₂ = 2 : 1

No. of moles of H₂ formed = (4.52 mol) × (1/2) = 2.26 mol

Molar mass of H₂ = 1.0 × 2 g/mol = 2.0 g/mol
Mass of H₂ formed = (2.26 mol) × (2.0 g/mol) = 4.52 g